PHP计算两个地点经纬度之间的距离代码php

/ / 2016-10-16   阅读:2492
<?php  function getDistanceBetweenPointsNew($latitude1, $longitude1, $latitude2, $longitude2) {     $theta = $longitude1 - $longitude2;     $miles = (sin(deg2rad($latitu...
<?php 
function getDistanceBetweenPointsNew($latitude1, $longitude1, $latitude2, $longitude2) {
    $theta = $longitude1 - $longitude2;
    $miles = (sin(deg2rad($latitude1)) * sin(deg2rad($latitude2))) + (cos(deg2rad($latitude1)) * cos(deg2rad($latitude2)) * cos(deg2rad($theta)));
    $miles = acos($miles);
    $miles = rad2deg($miles);
    $miles = $miles * 60 * 1.1515;
    $feet = $miles * 5280;
    $yards = $feet / 3;
    $kilometers = $miles * 1.609344;
    $meters = $kilometers * 1000;
    return compact('miles','feet','yards','kilometers','meters');
}

$point1 = array('lat' => 40.770623, 'long' => -73.964367);
$point2 = array('lat' => 40.758224, 'long' => -73.917404);
$distance = getDistanceBetweenPointsNew($point1['lat'], $point1['long'], $point2['lat'], $point2['long']);
foreach ($distance as $unit => $value) {
    echo $unit.': '.number_format($value,4).'<br />';
}
?>

我要评论

昵称:
验证码:

最新评论

共0条 共0页 10条/页 首页 上一页 下一页 尾页
意见反馈